Static equilibrium and tension problem

AI Thread Summary
The discussion revolves around a static equilibrium problem involving two horizontal scaffolds and a box of nails. Participants emphasize the importance of setting the forces equal to zero for the entire system and considering the sum of torques to determine the tension in the cables. The center of mass for the combined system of scaffolds and the box is crucial for calculating the effective tension distribution. It is clarified that while the total tension must equal the total weight, the individual tensions in the cables will vary based on their positions and the weight distribution. Understanding these concepts is essential for solving the problem accurately.
Puchinita5
Messages
178
Reaction score
0

Homework Statement



In Figure 12-36, horizontal scaffold 2, with uniform mass m2 = 35 kg and length L2 = 2.0 m, hangs from horizontal scaffold 1, with uniform mass m1 = 45 kg. A 17 kg box of nails lies on scaffold 2, centered at distance d = 0.50 m from the left end.
What is the tension T in the cable indicated?

Homework Equations


http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c12/q05f.jpg

The Attempt at a Solution


do i have to set the forces equal to zero for the WHOLE system? or the bottom system first? do I have to do anything with rotational? I think what is confusing me is how the tensions act in the system, specifically the tensions in the rods between the two scaffolds. I know there should be a tension force uppard in reaction to the weight of the bottom scaffold, so would the forces of the top scaffold include these tension forces? I'm confused. This is supposed to be a simple problem, perhaps I'm over thinking it.
 
Physics news on Phys.org
You might consider resolving the system into a single effective mass, and determine the center of mass and then use that to determine the final distribution of Tension between the 2 primary support cables.

Because to answer your question, yes. The system is static, and the sum of the Torques about any point are 0.
 
so i should find a center of mass, but the center of mass of both scaffolds? so i should do

(35)(1.5)+(45)(1.5)+(17)(1) all divided by 97? kind of as if i were to superimpose the top scaffold over the bottom scaffold?
 
Puchinita5 said:
so i should find a center of mass, but the center of mass of both scaffolds? so i should do

(35)(1.5)+(45)(1.5)+(17)(1) all divided by 97? kind of as if i were to superimpose the top scaffold over the bottom scaffold?

Yes. That's what I'd do.

Then use the total weight acting through the center of mass for it all.
 
and the tensions? would they all be the same magnitude?
 
Puchinita5 said:
and the tensions? would they all be the same magnitude?

The tensions must add to 97 if that's what you're asking. But they will be distributed unequally which is where you take your sum of the torques to figure it.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top