Static Equilibrium: Solving Homework Questions

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The discussion centers on solving static equilibrium problems in physics, specifically calculating tension in ropes. For one problem, it is established that the mass is in static equilibrium, leading to the conclusion that the tension in the rope is 40 N based on the sine function. Another participant expresses confusion about a different problem involving a 700 N weight and suggests that the tension in one rope must be greater. The conversation emphasizes the importance of understanding net forces and torques in static equilibrium scenarios. Overall, the participants are working through the complexities of applying equilibrium principles to solve homework questions.
Meezus
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Homework Statement



rHgvVyw.png


Homework Equations

The Attempt at a Solution


[/B]
8)
The mass is in static equilibrium meaning the sum of all the forces acting on it are equal to 0.
Both sides are holding have the same tension because they have the same angle.
SINΘ = (Opposite) / Hypotenuse
= Hypotenuse = (Opposite) / SINΘ
= 20) / (SIN 30)
= 20 / 0.5
= 40

The tension in the rope equals 40 N?

9)
I'm totally clueless where to start on this one.
I'm totally guessing here but It must have something to do with the man weighing 700 N within the first 2M.
So rope X must have higher tension.
 
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In 9 you have to do like you did in 8 and use the idea that the net force on the beam is zero. This will not tell you, however, the magnitude of the tension force in each rope, only their sum. But that is the first step. The next step is to use the idea that the net torque on the beam is zero.
 
Meezus said:

Homework Statement



rHgvVyw.png


Homework Equations

The Attempt at a Solution


[/B]
8)
The mass is in static equilibrium meaning the sum of all the forces acting on it are equal to 0.
Both sides are holding have the same tension because they have the same angle.
SINΘ = (Opposite) / Hypotenuse
= Hypotenuse = (Opposite) / SINΘ
= 20) / (SIN 30)
= 20 / 0.5
= 40

The tension in the rope equals 40 N?
By using the sine of the angle here, are you calculating the tension in the line, or something else?

Remember, the tension in each line will form the hypotenuse of the force triangle.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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