Static friction for a ball rolling without slipping

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Homework Help Overview

The discussion revolves around the dynamics of a bowling ball rolling without slipping up a ramp inclined at an angle β. Participants explore the direction of the static friction force and its relationship with the forces acting on the ball, particularly gravity.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants examine the relationship between the direction of static friction and the motion of the ball, questioning how gravity influences the friction force. There is a focus on understanding the conditions under which static friction acts uphill or downhill.

Discussion Status

The conversation is active, with participants offering insights into the nature of rolling motion and the implications for friction. Some have provided clarifications regarding the instantaneous velocity of the contact point and its relevance to static friction.

Contextual Notes

There is an ongoing exploration of the definitions and implications of rolling without slipping, as well as the assumptions about the forces acting on the ball. The discussion reflects a mix of interpretations regarding the role of static friction in different scenarios.

Lola Luck
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Homework Statement



A bowling ball rolls without slipping up a ramp that slopes upward at an angle β to the horizontal. Treat the ball as a uniform solid sphere, ignoring the finger holes. Explain why the friction force must be directed uphill.

Homework Equations



F=ma, torque=I(alpha), a=r(alpha) (I don't think I need any of these for this question)

The Attempt at a Solution



I thought that because the instantaneous velocity for the contact point is in the downhill direction, the friction force must act uphill. However there's an example in my textbook in which the ball rolls downhill and the force of static friction is still uphill. Apparently, the force of friction acts uphill wether the ball is rolling uphill or downhill.
 
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Lola Luck said:
I thought that because the instantaneous velocity for the contact point is in the downhill direction, the friction force must act uphill.
This would be correct if the friction was kinetic friction. But, if the ball rolls, then the contact point does not slide (the instantaneous velocity of the contact point is zero!) and so the friction is static, which means it is free to act in either direction.
 
Ok, so how do I know it's uphill in this case? I think it's because gravity acts downhill and the force of static friction has to oppose gravity.
 
Lola Luck said:
I think it's because gravity acts downhill and the force of static friction has to oppose gravity.
It can act in either direction that it needs to. The key is that the ball is rolling the whole time. What does it mean for the ball to be rolling?
 
That it's accelerating? I'm not sure what you mean.
 
Rolling means there is a special relationship between the angular velocity and the linear velocity.
Look at your "relevant equation"
Lola Luck said:
a=r(alpha)
or equivalently, v=r\omega where v is the linear velocity and ω is the angular velocity.
 
If the linear velocity is decreasing (it should be due to gravity), the rotational velocity also decreases. So static friction needs to act uphill to slow the ball down?
 
Lola Luck said:
If the linear velocity is decreasing (it should be due to gravity), the rotational velocity also decreases. So static friction needs to act uphill to slow the ball down?
Exactly :)
If the linear velocity is decreasing, then the torque (from friction) must slow the ball's rotation.
 
This topic makes so much more sense now. Thank you for your help! :)
 
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  • #10
To clarify one point:
Lola Luck said:
the instantaneous velocity for the contact point is in the downhill direction
In rolling contact with a stationary surface, the point of contact of the wheel/ball is instantaneously stationary.
 

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