The discussion centers on the calculation of static friction on an inclined plane, specifically addressing the confusion between the equations f = mg cos(theta) and f = mg sin(theta). The correct equation for the frictional force, which opposes the motion of the block, is f = mg sin(theta), as this represents the component of gravitational force acting parallel to the incline. The participants clarify that the frictional force is distinct from the normal force, which acts perpendicular to the surface.
PREREQUISITESStudents studying physics, particularly those focusing on mechanics, as well as educators looking for clear explanations of static friction concepts on inclined planes.
rl.bhat said:In the problem, f is the frictional force ,not the normal reaction.
Frictional force acts in the opposite direction of the motion of the block.The block moves down due to the component of weight along the inclined plane. What is that component?