rl.bhat said:In the problem, f is the frictional force ,not the normal reaction.
Frictional force acts in the opposite direction of the motion of the block.The block moves down due to the component of weight along the inclined plane. What is that component?
Static friction on an inclined plane is the force that prevents an object from sliding down the plane due to the component of its weight that is acting parallel to the surface. It is the frictional force between the object and the surface of the inclined plane.
The static friction force on an inclined plane is calculated using the formula Fs = μsN, where Fs is the static friction force, μs is the coefficient of static friction, and N is the normal force perpendicular to the surface of the plane.
The magnitude of static friction on an inclined plane is affected by the coefficient of static friction, the weight of the object, and the angle of the incline. The roughness of the surface and the presence of any external forces may also impact the magnitude of static friction.
The angle of the inclined plane affects the magnitude of static friction by changing the normal force acting perpendicular to the surface. As the angle increases, the normal force decreases, resulting in a decrease in the static friction force.
Yes, static friction on an inclined plane can be greater than the weight of the object if the angle of the incline and the coefficient of static friction are large enough. In this case, the object will not slide down the plane, and the static friction force will be equal to the component of the weight acting parallel to the surface.