How Does the Cross Product Help Calculate Tension in a Cable?

AI Thread Summary
The discussion centers on calculating the tension in a cable supporting a horizontal boom and sign, with the total weight being 200 N. The cross product can be applied to determine the tension, but the angle of the cable relative to the horizontal is crucial for an accurate calculation. Participants express the need for additional information, such as the lengths involved and the specific angle of the cable. A diagram is referenced to clarify the setup, emphasizing the importance of visual aids in solving the problem. Overall, the tension in the cable is influenced by its angle, necessitating further details for precise computation.
Shay10825
Messages
337
Reaction score
0
In the problem:
A horizontal boom supporting the sign is of uniform construction and weighs 50 N. If the sign weighs 150 N, the tension in the supporting cable is?

Could I use the cross product and if so how? The answer is 350 N.
 
Physics news on Phys.org
Do you have a diagram? Is the cable at an angle, or is it vertical? Where's this sign you mention?
 
http://img121.exs.cx/img121/4286/2882.jpg
 
Hmmm...is that all the info? Do we have some lengths, or the angle of the cable from the horizontal?
 
The tension in the cable definitely depends on the angle it makes with the horizontal, so we need to know that to solve the problem.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top