Statics - Finding Reaction at Supports

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SUMMARY

This discussion focuses on analyzing static equilibrium in structures, specifically finding reactions at supports in a system with multiple connection points. The user seeks clarification on drawing free body diagrams for a structure connected at four points, particularly when angles complicate the analysis. A suggestion is made to simplify the model by removing a horizontal member that does not contribute to the force analysis. Additionally, the concept of temporarily replacing a pin support with a fixed support is introduced to facilitate load distribution calculations.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of free body diagram construction
  • Familiarity with support types (pin and fixed supports)
  • Basic concepts of load distribution in structural analysis
NEXT STEPS
  • Study the method of drawing free body diagrams for complex structures
  • Learn about the effects of fixed and pin supports on load distribution
  • Explore the principles of static equilibrium in multi-support systems
  • Investigate simplification techniques in structural analysis
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Engineering students, structural analysts, and professionals involved in civil engineering or mechanics who require a deeper understanding of static systems and support reactions.

adam640
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Hey I'm just going over a past paper and I've lost the section of my notes RE this topic.

I understand how to draw the free body diagram when there is a pin involved, but not when it is connected at 4 points, the fact that they're at an angle is not helping.

Any help greatly appreciated, thanks in advance.

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I don't see the horizontal member to the right of X contributing any force. It can be removed to simplify your analysis.
 
Been 30 years sinvce I did this but ...

The lower supports are fixed so can point X be temporaily replaced by a fixed support? The 20kN load is therefore shared equally between the one support to the left and the temporary support at X. The vertical load on the temporary support X is then transferred down to two lower supports.
 

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