Statics: Method of Joints (Truss)

AI Thread Summary
The highlighted force in the truss analysis is zero due to the equilibrium condition, where the sum of forces in the x-direction must equal zero. If a force, such as BD, were present, it would necessitate an equal and opposite force to maintain equilibrium, which raises questions about its placement. The discussion emphasizes the importance of understanding how forces interact within the system to achieve balance. The calculations for forces like FDC and FDE are crucial for determining the overall stability of the truss. Understanding these concepts is essential for solving problems related to statics and truss analysis.
Vanessa Avila
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Can someone explain to me why that highlighted force is 0?
moj.JPG


Homework Equations


∑Fx = 0

The Attempt at a Solution


I found FDC to be 780lb and I am still trying to solve for FDE
 
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If BD was non zero, let's just say for example it was 100 pounds , then 100 lbs in the opposite direction would be required for equilibrium along that axis. Where would that required opposite force go?
 
Thread 'Have I solved this structural engineering equation correctly?'

Thread 'Have I solved this structural engineering equation correctly?'

Hi all, I have a structural engineering book from 1979. I am trying to follow it as best as I can. I have come to a formula that calculates the rotations in radians at the rigid joint that requires an iterative procedure. This equation comes in the form of: $$ x_i = \frac {Q_ih_i + Q_{i+1}h_{i+1}}{4K} + \frac {C}{K}x_{i-1} + \frac {C}{K}x_{i+1} $$ Where: ## Q ## is the horizontal storey shear ## h ## is the storey height ## K = (6G_i + C_i + C_{i+1}) ## ## G = \frac {I_g}{h} ## ## C...
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