Statics Problem (tension, and a distance)

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The discussion revolves around a statics problem involving block A, which has a mass of 250 kg, supported by a cable. The user is attempting to determine the tension in the cable and the distance x when the system is in equilibrium. Confusion arises regarding the calculation of tension, with the user mistakenly believing it varies along the cable, while others clarify that it remains constant. The user has calculated angles and attempted to apply the sum of forces in both x and y directions but struggles to find the correct values for tension and distance x. Ultimately, the conversation emphasizes the importance of correctly applying static equilibrium principles and geometry to solve the problem.
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Okay, i posted a picture of the problem above, sorry if blurry, do not have scanner. i will retype problem,

The mass of block A is 250 kg. Block A is supported by a small wheel that is free to roll on the continuous cable between supports B and C the length of the cable is 42 m. Determine the distance x and the tension T in the cable when the system is in equilibrium.

I tried doing a sum of forces in x and y components and equal to zero but i am not getting it.

I am wondering, is the tension throughout the whole cable going to be 250(9.81)? or is it different for each side of the weight?

Any help on where to go is helpful thank you.
 
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Hi yopy! :smile:
yopy said:
I tried doing a sum of forces in x and y components and equal to zero but i am not getting it.

I am wondering, is the tension throughout the whole cable going to be 250(9.81)? or is it different for each side of the weight?

(As the question suggests, the tension should be the same all the way along a rope or cable)

Sorry, but if you get 250(9.81), you're doing it completely wrong :redface:

Show us your full calculations, and then we can see what went wrong, and we'll know how to help. :smile:
 
tiny-tim said:
Hi yopy! :smile:


(As the question suggests, the tension should be the same all the way along a rope or cable)

Sorry, but if you get 250(9.81), you're doing it completely wrong :redface:

Show us your full calculations, and then we can see what went wrong, and we'll know how to help. :smile:

250(9.81) was not my final answer but the calculated value i got for T(tension) in the wire. from there i do not know where to go.

i tried doing sum of forces in x and y coordinates but my 2 unknowns were fetaA and fetaB which were the angles from the x-axis to the cord. when i worked it out i got that the angles were the same but i think its wrong
 
i worked through this above statement and found that both angles to the left and right of the weight, from the x-axis to the line, is 30 degrees. I am pretty sure i calculated it right but it seemed to be a lot of work for the problem. but from 30 degrees i can't think of anywhere to go from there to get X so i think i did it the wrong way. Also, this is in a chapter that doesn't teach moments. moments are taught after this chapter so i don't think your supposed to use moments.
 
yopy: You are correct that both angles are the same. Now it is just a matter of geometry to figure out the angle and lengths, and the value of x. Your 30 deg angle appears to be incorrect. Try again. Last, compute the cable tension T using static equilibrium. No moments are required.
 
yopy said:
250(9.81) was not my final answer but the calculated value i got for T(tension) in the wire.

Sorry, but that is wrong.

Please show us the equations you got for the horizontal and vertical components of force.
 
tiny-tim said:
Sorry, but that is wrong.

Please show us the equations you got for the horizontal and vertical components of force.

okay i did FBD, i have 3 forces, one acting on the string to the left, one acting on the string to the right and the weight in Y direction negative. i called the angles to the left and right FetaA and B

sum Fx = 0 = -Tcos(fetaA)+Tcos(fetaB)
sum Fy = 0 = -w + TsinFetaA +tcosfetaB

from Fx i came to conclusion that both angles are the same?

then i tryed to find T but i can't find it... since angles are same i figured that x will come out to be the same value as long as i use the same 2 angles for fetaA and fetaB. i worked through a lot of geometry of angles and law of sines and found X. but i can't get T.
 
Hi yopy! :smile:
yopy said:
sum Fx = 0 = -Tcos(fetaA)+Tcos(fetaB)
sum Fy = 0 = -w + TsinFetaA +tcosfetaB

from Fx i came to conclusion that both angles are the same?

then i tryed to find T but i can't find it... since angles are same i figured that x will come out to be the same value as long as i use the same 2 angles for fetaA and fetaB. i worked through a lot of geometry of angles and law of sines and found X. but i can't get T.

(i assume you meant to type sum Fy = 0 = -w + TsinFetaA + TsinfetaB ?)

(oh, and have a theta: θ and try using the X2 tag just above the Reply box :wink:)

Well, T is just w/2sinθ, so if you've found x, you should have also found sinθ …

what did you get for x and θ? :smile:
 
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