Stationary Electron accelerated through potential difference

AI Thread Summary
To find the velocity of a stationary electron accelerated by a potential difference of 500V, the relevant equation is derived from energy conservation: qV = (mv^2)/2. Rearranging this gives the velocity as v = (2qV/m)^(1/2). In this case, q represents the charge of the electron, V is the potential difference, and m is the mass of the electron. The correct formula simplifies to v^2 = 2eV/m, confirming the relationship between energy and velocity for charged particles in electric fields. Understanding this concept is crucial for solving similar physics problems.
dr.mt
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I have this question that asks what the velocity of the stationary electron is after being accelerated by potential difference. The potential difference is 500v, but the specific potential difference doesn't concern me. I'm uncertain of how i get the velocity, because i don't know an equation for velocity affected by potential difference. i feel as though this is incredibly simple and I'm missing something.
 
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Do you know what the energy might be?
 
Oh alright, yep simple mistake. it'd be qV=(mv^2)/2 converted to veloctiy= (2qV/m)^(1/2) right?
 
Thank you ZapperZ. v^2= 2eV/m
 

Thread 'Why measure the speed of light in one direction?'

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