Stationary particle in a laser beam

Dart82
Messages
56
Reaction score
0

Homework Statement

A stationary particle of charge q = 3.0 10-8 C is placed in a laser beam whose intensity is 2.5 103 W/m2.

(a) Determine the magnitude of the electric force exerted on the charge.

(b) Determine the magnitude of the magnetic force exerted on the charge.




Homework Equations


Force on a charge--> F=qE
S = cu
u = (1/2)εo*E^2




The Attempt at a Solution


a.) i am given S and i know c so i can find u by S/c = u.
now that i have u i can solve for E using u = (1/2)εo*E^2.
I multiply E times q to get F.
sounds easy enough and makes sense to me, however i am doing something wrong here huh?

b.) i know that the magnitude will be zero since the charge is stationary.
 
Physics news on Phys.org
Looks OK to me.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top