Statistic mechanics - particles with energy 0

AI Thread Summary
The discussion centers on a homework problem involving a system of weakly interacting particles in thermal equilibrium with three energy states: -epsilon, +epsilon, and 0. Participants express confusion about how to derive the fraction of particles with energy 0, which is stated to be sqrt(3)/(4+sqrt(3)). The relevant equation for calculating the probabilities of particles in different energy states is confirmed as P(E_i)=e^{-E_i/kT}/(sum_j e^{-E_j/kT}). Users collaborate to clarify the ratios of probabilities for the -epsilon and +epsilon states, ultimately leading to a better understanding of the problem. The thread concludes with participants expressing gratitude for the assistance received.
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Homework Statement


System of weakly interacting particles in equilibrium temperature T, each particle can exist in three energy states -epsilon, +epsilon and 0. There are three times as many particles in the -epsilon state as in the +epsilon state. Show that fraction of particles with energy 0 is sqrt(3)/(4+sqrt(3)) ?



Homework Equations


No idea how to go about this



The Attempt at a Solution

 
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There's an equation that gives the relative probability, or number, of particles occupying different energy states. Should be in your textbook or class notes ... it contains the number e, as well as T and k.
 


is it along the lines of P(E_i)=e^{-E_i/kT}/(sum_j e^{-E_j/kT})

thats probably wrong but could you confirm please...
 


Yes, that's the one.
 


I'm stuck on the same question. I have the expression for the probabilities but I can't get the final expression they have. Any chance of another hint? I've been staring at this for a while and getting nowhere.
 


latentcorpse said:
P(E_i)=e^{-E_i/kT}/(sum_j e^{-E_j/kT})

Use this ↑ equation to write an expression for the ratio:

P(E=-ε) / P(E=+ε)
 


Redbelly98 said:
Use this ↑ equation to write an expression for the ratio:

P(E=-ε) / P(E=+ε)
Was stuck at this too! I get it now. Thanks!
 


Yeah, thanks for the help. I got it too.
 
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