Steady state conduction in a hollow sphere

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SUMMARY

The discussion focuses on steady state conduction in a hollow sphere, specifically addressing a calculation error in determining heat transfer rate. The user provided dimensions and temperatures: inner radius (ri) of 0.01 m, outer radius (ro) of 0.02 m, inner temperature (Ti) of 70 °C, outer temperature (To) of 100 °C, and thermal conductivity (k) of 0.58 W/m K. The user initially calculated a heat transfer rate (q) of 2.18 W, but the correct value is -4.37 W, attributed to an incorrect substitution in the formula, specifically using (1/ri - 1/ro) in the denominator.

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rcummings89
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Hello,

I'm having trouble with a conduction problem, I have access to the answer but not the solution. I did it on my own and my value is half of what the answer is. Now, my calculus is a little rusty, but I don't know where I am going wrong. So the dimensions and temperatures of the sphere are:

ri=0.01 m
ro=0.02 m
Ti=70 oC
To=100 oC
k=0.58 W/m K

Attempt:

q/A = -k dT/dr

q/A dr = -k dT

Where A = 4\pir2 then

q ∫ dr/r2 evaluated from ri to ro = -4 \pi k ∫ dT from Ti to To yields...

-q (ro-1 - ri-1) = -4 \pi k (To - Ti)

Substituting in the values, I get q = 4 \pi [(0.58)(100-70)](0.02-0.01) = 2.18 W

The actual answer is double that and negative, -4.37 W. Any idea what I'm doing wrong?

Thanks in advance!
 
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Your algebraic solution is correct, but you substituted into it incorrectly. The problem is with the ro and ri. You should have (1/ri-1/ro) in the denominator.
 

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