Sterling Approximation for Einstein Solid Multiplicity

[Barley]

How does the following expand;

(q + N )*ln(q +N)

I'm Trying to arrive at sterling approximation for the multiplicity for einstein solid where q>>N. Any tips appreciated.

Thanks

 

[stunner5000pt]

factor out the bigger of the two

q(1 + \frac{N}{q} \ln q(1 + \frac{N}{q})

i gues you could 'expand it using the log expansion
ln (1+x) = x - \frac{1}{2} x^2 + \frac{1}{3} x^3 - ...

 

[Barley]

Thanks,

I'm going to have to see my prof. on this one. I'll let you know how it works out if you'd like.

 

[dextercioby]

I guess N stands for the number of particles (phonons), so it should be the "bigger" one. I also think that Stirling's approximation involves factorials.


Daniel.

 

[Barley]

For my next exercise I'm to derive the case where N >> q. In these simple idealized cases of 2 solids interacting. So big q is high temp case- I think.
I've already used the sterling approximation to get the factorials out of the equation and now I'm just hashing it into best form.

many thanks.