- #1

thonwer

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## Homework Statement

We have a stick which is vertical, its length is 2m and its weight 45.9kg. A string is pulling the top of the stick from the floor at a distance of 2m from the left of the bottom of the bar. A force of 100N is pulling from the right at the middle of the stick. Which has to be the friction coefficient for the friction force acting on the bottom of the stick? The stick has to be in rest.

https://imagizer.imageshack.us/v2/800x600q90/607/kb5l.jpg

## Homework Equations

F=ma

p=mg

R=u*N

u=(friction coefficient)

N=(normal reaction)

p=weight

T=tension

## The Attempt at a Solution

y axis: p+Ty=N -> N=p+Tcos(Θ)

x axis: F=R+Tx ->F=uN+Tsin(Θ) -> u=([itex]\frac{F-Tsin(Θ)}{p+Tcos(Θ)}[/itex])

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