Chemistry Stoichiometry - transferable mole values?

AI Thread Summary
To find the mass of HCl produced from the reaction yielding 18.7g of H3PO4, first calculate the moles of H3PO4, which is 0.190815119 mol. The stoichiometry of the reaction indicates that for every mole of H3PO4 produced, five moles of HCl are generated. Therefore, the moles of HCl would be 0.190815119 mol multiplied by 5, resulting in 0.954075595 mol of HCl. After determining the moles of HCl, calculate its mass using its formula weight. This approach confirms the relationship between the moles of H3PO4 and HCl based on the coefficients in the balanced equation.
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Homework Statement



I have to find the mass of HCl (in grams) that is produced given the below reaction yields 18.7g of H3PO4.

Homework Equations



PCl5 + 4H20 -> H3PO4 + 5HCl

The Attempt at a Solution



I calculated the # of mols for H3PO4.

I want to confirm if this mol value (0.190815119mol) is also the # of mol of H and # of mol of Cl, with regrards to HCl.. or is the number of mols of each of H and Cl fives times that of 0.190815119mol because of the coefficient "5"HCl ?

Thanks!
 
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Use stoichiometric mole ratio found in the reaction statement to calculate moles of resulting HCl.
Calculate formula weight of HCl and use this to calculate the mass of HCl.
 
The chemical equation says that for each mole of PCl5 consumed you get 5 moles of HCl, so you would need to multiply 0.191 mol by 5 to get the number of moles of HCl.
 
Alrighty, thanks for the clarification!
 
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