Stopping a Box of Unknown Mass on Frictionless Floor

AI Thread Summary
A box with an initial speed of 4.7 m/s slides onto a rough section of a frictionless floor, where the coefficient of friction is 0.3. To determine the shortest length of rough floor needed to stop the box, the frictional force is calculated using the normal force and the coefficient of friction. The acceleration due to friction is found to be equal to the coefficient of friction multiplied by gravitational acceleration. By applying the equation vf^2 = vi^2 + 2a delta x, the box's stopping distance can be computed. Understanding the relationship between friction, normal force, and acceleration is crucial for solving this problem effectively.
TG3
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Homework Statement


A box of unknown mass slides across a frictionless floor with an initial speed of 4.7 m/s. It encounters a rough region where the coefficient of friction is µk = 0.3
Part 1:
What is the shortest length of rough floor which will stop the box?
Part 2:
What is the shortest length of rough floor which will stop the box?

Homework Equations



vf^2 = vi^2 + 2a delta x.
Frictional force = mew times the normal force

The Attempt at a Solution


Final velocity = 0, so
0 = 4.7 ^2 + 2A delta x.
A = the frictional force.
How can I determine the normal force (and after that, the frictional force, and after that, the change in distance) if I don't know the weight of the box? Is there another way to do this problem?
 
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F = ma = μ*m*g

a = μ*g

Does that help?
 
Yes- it certainly does. With that I was able to solve both parts of the problem. I'm writing that formula down for future reference...
 
TG3 said:
Yes- it certainly does. With that I was able to solve both parts of the problem. I'm writing that formula down for future reference...

Better to understand it and remember it forever.
 
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