Not really. Think about how the stream function and velocity potential are related to the velocity in a two-dimensional flow:
[tex]u = \dfrac{\partial \phi}{\partial x} = \dfrac{\partial \psi}{\partial y}[/tex]
[tex]v = \dfrac{\partial \phi}{\partial y} = -\dfrac{\partial \psi}{\partial x}[/tex]
If you have something along the lines of [itex]\phi = f(x,y) + C[/itex] or [itex]\psi = g(x,y) + C[/itex], then when you take its derivative and extract a velocity, the constant [itex]C[/itex] falls out anyway. In that sense, the constant is arbitrary and doesn't matter. You only need the general solution to the differential equation, not the specific solution for a given set of boundary conditions.
If instead you are looking at the value of [itex]\psi[/itex] or [itex]\phi[/itex] directly (for instance, for plotting streamlines or equipotential lines), then the constant does mean something. In that case, if you look in a 2D plane, setting an actual value for [itex]C[/itex] and holding it constant while you vary the other parameters in your equations [itex]f(x,y)[/itex] and [itex]g(x,y)[/itex], the resulting paths will trace out the equipotential lines and streamlines in the [itex](x,y)[/itex]-plane for [itex]f[/itex] and [itex]g[/itex] respectively.
For example, if you want to plot the stagnation streamline on a body in potential flow, you would use some point that you know on that streamline (typically the stagnation point itself) and use its coordinates in your function [itex]g(x,y)[/itex] to find the value of the constant. Then, in varying one coordinate to find the other, you will trace out the stagnation streamline. Or you could just pick random values of the constant to map out random streamlines to your heart's content.