Stresses and strains in steel sheet

  • Thread starter Thread starter *Alice*
  • Start date Start date
  • Tags Tags
    Steel
*Alice*
Messages
26
Reaction score
0
Dear all, I am trying to calculate the stresses and strains induced by a 40K change in temperature of a steel sheet of thickness 5mm, that is clad on both sides with 2mm thick layers of copper. For both materials E, alpha (í.e. the thermal expansion coefficient), as well as v (Poissons ratio are given).

My attempt was equating the forces (see attached word document).

This does unfortunately not work and the fact that the Poisson ratios are given makes me think that I have missed something out. Can anyone help?

Thanks a million for any help, hints and suggestions.

Alice
 

Attachments

Physics news on Phys.org
I do not see why the temperature change would induce a stress in the specimen as it is free to expand? Could you provide the full question?
 
where is the geometry?
 
The questions says:

A steel sheet of thickness 5cm is clad on both sides with 2mm thick layers
of copper. Determine the stresses and strains induces by a 40K change in
Temperature

given Data:

for steel: E=210kN/mm^2, v=0.3 (Poissons ratio), alpha=11*10^(-6) 1/K
for copper: E =180 kN/mm^2, v=0.35, aplpha = 30*10^(-6) 1/K

Solution: 70 N/mm^2, 87.5N/mm^2, 0.673 millistrain, 0.24millistrain, 1.77
millistrain


I thought there was geometry, since the steel is clad on top and bottom with 2mm thick layers of copper.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...

Similar threads

Back
Top