Student Struggling with Hookes Law - 18 Year Old Physics Student

AI Thread Summary
Hooke's Law describes the linear relationship between the force applied to a spring and its extension, stating that the force (F) is proportional to the displacement (Δx) with the equation F=kΔx, where k is the spring constant. To calculate the constant k, one can hang weights from the spring and plot the weight (mg) against the change in length, with the slope of the resulting line representing k. While many materials follow Hooke's Law, rubber does not due to its complex polymer structure, which leads to non-linear behavior and hysteresis during stretching and unloading. Understanding these principles is crucial for mastering mechanics in physics. The discussion emphasizes the importance of grasping these concepts for upcoming exams.
z3sh4n
Messages
2
Reaction score
0
hi, I am a student 18 years of age, I am currently starting my first year of physics, and I've got an exam coming up, on mechanics, materials and waves


i can't seem to get a grip on hookes law, could someone explain it please?
 
Physics news on Phys.org
Hi there,

The Hookes law simply models the extension of a spring under a load. If you have a spring that follows this law, then it simply says that the force applied to the spring will extend the spring. If you double this force, you double the extension of the spring.

Cheers
 
A spring that obeys Hooke's law, when displaced from its equilibrium position by a distance \Delta x, exerts a force which acts to compress the spring if it has been stretched or vice versa with magnitude F=k \Delta x where k is the spring constant. The point is that the force directed towards the equilibrium point increases linearly with displacement.
 
thanks very much for that.

but how would you calculate the constant k

and what about the rubber not obbeying hookes law. when i was doing a past paper that is one of the questions that actually came up, i could slighty figure it out but other wise i was completely lost
 
Hi there,

Elastic might follow Hookes' law. To find out, apply a certain force to the spring/rubber and measure the deformation. By doubling the force applied to it, verify that the elongation double also. If so, then you device follows Hookes' law.

Cheers
 
z3sh4n said:
thanks very much for that.

but how would you calculate the constant k

and what about the rubber not obbeying hookes law. when i was doing a past paper that is one of the questions that actually came up, i could slighty figure it out but other wise i was completely lost

The easiest way to measure 'k' (especially for a spring) is to hang weights off one end; plotting mg versus the change in length gives (approximately) a line, the slope of which is 'k'.

Most materials do not obey Hooke's law (it's a linear approximation). Non-linear theories of elasticity are much more complex.
 
z3sh4n said:
thanks very much for that.

but how would you calculate the constant k

and what about the rubber not obbeying hookes law. when i was doing a past paper that is one of the questions that actually came up, i could slighty figure it out but other wise i was completely lost

Because of its polymetric structure rubber does not obey Hooke's law.It stretches easily at first because the polymer chains are being straightened but once straightened it becomes harder to stretch because the molecules themselves are being separated.Rubber also displays something called hysteresis and recovers by a different route when it is unloaded.
 

Similar threads

Back
Top