How Do You Simplify 4√(sin(π/4))?

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To simplify 4√(sin(π/4)), the key steps involve recognizing that sin(π/4) equals √2/2. This leads to the expression simplifying to 4√(√2/2), which can be rewritten as 4√(√2) / √2. Further simplification reveals that this equals 2 * 2^(3/4). The discussion emphasizes the importance of manipulating exponents and recognizing equivalent forms to reach the final simplified result. Understanding these steps allows for a clearer path to the solution without relying on technology.
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I've come across this before, but for the life of me can't seem to get anywhere with it. I can plug this into technology and get an answer (and then move on...), but I want to know how to do it without.

An example problem:

4\sqrt{\sin(\pi/4)}

I get as far as

2\sqrt{2\sqrt{2}} = 2(2(2)^\frac{1}{2})^\frac{1}{2}

but then I run out of steam and don't see the next step. Surely it is something simple that I am missing, but I just don't see it.

Thanks for any tips. Cheers!
 
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I don't know what you're asking, but since 2\sqrt{2}=\sqrt{8}, it equals two times the quartic root of 8...
 
I have \sqrt{8} as an intermediate step in my work.

<br /> <br /> 4\sqrt{\sin(\pi/4)} = \sqrt{\frac{16\sqrt{2}}{2}} = \sqrt{8\sqrt{2}} = \sqrt{4*2\sqrt{2}} = 2\sqrt{2\sqrt{2}}<br /> <br />

When I plug into technology, I get the answer:

<br /> <br /> 2*2^\frac{3}{4}<br /> <br />

but I don't know how to get there. That's what I'm asking; sorry for being unclear.
 
Well, yeah.

Going with my two times quartic root of 8 solution, since 8 is 2 cubed, the quartic root of 8 is 2 to the three-fourths power, and the number simplifies to your number.
 
Of course. Thank you very much! I definitely should've seen that! :)

Cheers.
 
2h2o said:
I've come across this before, but for the life of me can't seem to get anywhere with it. I can plug this into technology and get an answer (and then move on...), but I want to know how to do it without.

An example problem:

4\sqrt{\sin(\pi/4)}

I get as far as

2\sqrt{2\sqrt{2}} = 2(2(2)^\frac{1}{2})^\frac{1}{2}

but then I run out of steam and don't see the next step. Surely it is something simple that I am missing, but I just don't see it.

Thanks for any tips. Cheers!

When you multiply a two numbers with the same base, the exponents add. So,

2(2^{1}*2^{\frac{1}{2}})^{\frac{1}{2}} = 2(2^{1+\frac{1}{2}})^{\frac{1}{2}} = 2(2^{\frac{3}{2}*\frac{1}{2}}) = 2*2^{\frac{3}{4}}
 
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