Subgroup of D_n: Proving <f> Not Normal

  • Thread starter Thread starter rapple
  • Start date Start date
  • Tags Tags
    Subgroup
rapple
Messages
25
Reaction score
0

Homework Statement



S.T <f> is not normal. where f is a reflection

Homework Equations


<f>={e,r^0 f, r^1f,r^2f,..}
WTS For any g in D-n, g(r^kf)g^-1 Not In <F>

The Attempt at a Solution


Elements of D-n are r^k, r^kf
For r^k, (r^k)(r^if)(r^-k) is in <f>.

So I am stuck
 
Physics news on Phys.org
rapple said:
WTS For any g in D-n, g(r^kf)g^-1 Not In <F>

No. You want to show there exists such a g. Just find one.
 
The subgroup generated by f, which is what <f> usually means, is just {e,f} with e the identity. What you wrote is in fact all of D_n. You probably should write in proper sentences so that everyone is sure what you mean (i.e. no abbreviations that might not be universally understood) - reading mathematics is hard at the best of times, so please help us out and make it as easy as possible.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top