Sum, difference and equality puzzle

AI Thread Summary
The discussion centers on solving a cryptarithmetic puzzle involving the equation GEORGE + RUGGLE + 15750 + 16220 + P = PPPPPP, along with the relationships OE - LR = LO and the divisibility condition for RUGGLE. It is established that RUGGLE must be a six-digit number divisible by both 7 and 5, indicating it is a multiple of 35. Given the constraints, RUGGLE must range from 123375 to 987735, with R being a non-zero digit. The value of E is deduced to be either 0 or 5, leading to the conclusion that E is a multiple of 5. The equation for O is derived from OE - LR = LO, and further calculations reveal that P can be expressed in terms of the digits involved. The approach involves enumerating possible values for RUGGLE, calculating O and P, and checking the conditions to find a unique solution.
K Sengupta
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Substitute each of the capital letters by a different digit from 0 to 9 to satisfy this set of cryptarithmetic relationships. None of the numbers can contain any leading zero.

GEORGE + RUGGLE + 15750 + 16220 + P = PPPPPP, and:

OE - LR = LO, and:

RUGGLE is divisible by 7
 
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E=0 I think
 
Since E + E + P -> P, E must be either 0 or 5, so E is a multiple of 5.

RUGGLE is a multiple of 7 and a multiple of 5, so ruggle is a multiple of 35.

With RUGGLE being 6 digits and R nonzero, that means that the lowest value for RUGGLE is 123375 and the highest 987735.

With OE - LR = LO it follows that O = (20 x L + R - E) / 9

Looking at the 5th digit of the sum it follows that:
P = (G + L + 5 + 2 + 2 x E / 10) mod 10

Now we can simply enumerate all possible values of RUGGLE, calculate O and P and check if the conditions are met.
Finally only 1 answer remains.

george + ruggle + 15750 + 16220 + p = pppppp oe - lr = lo
609160 + 136640 + ... + ... + 7 = 777777 90 - 41 = 49
 
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