Sum of branch currents more than total current?

[ViolentCorpse]

Homework Statement

An impedance of 7-2jΩ and an impedance of 4+2jΩ and a current source of 97.5A are all connected in parallel. Find the individual branch currents.

Homework Equations

Current-divider rule:

I1=I*Z1/(Z1+Z2) (only have to consider the magnitudes of the impedances, not the angle)

The Attempt at a Solution

I've obtained a value of I1=39.54A and I2=64.53A. However, these currents sum up to 104.07A, whereas the current source is supplying a current of only 97.5A. Why is there a discrepancy?

 

[milesyoung]

For complex current I1 and I2 it's true that I1 + I2 = (97.5 + j*0) A, but it doesn't follow that |I1| + |I2| = |(97.5 + j*0)| A

 

[ViolentCorpse]

Oh, I see. My bad.

Thank you very much, milesyoung!