Sum of the infinite series ((-1)^n * (-7)^n)/n

Erubus
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Homework Statement



Find the sum of infinite the series (-1)^n * 7^n/n! for n=1 to infinity

Homework Equations



e^x = sum (x^n)/n! for n=0 to infinity

The Attempt at a Solution



I combined the (-1)^n and the 7^n to make the summation ((-7)^n)/n! for n = 1 to infinity

then I changed the lower bound to 0 to make it similar to e^x

((-7)^(n+1))/(n+1)! for n=0 to infinity

I don't know where to go from here, help would be appreciated!
 
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Erubus said:
I combined the (-1)n and the 7n to make the summation ((-7)n)/n! for n = 1 to infinity

then I changed the lower bound to 0 to make it similar to ex

((-7)n+1)/(n+1)! for n=0 to infinity

instead of changing the limits, just add a "0th" term …

-1 + ∑0 (-7)n/n! :wink:
 
Wow never would have thought of that, but it makes sense.

Thanks!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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