Superconductor in an external magnetic field

AI Thread Summary
The discussion focuses on analyzing a superconducting spherical shell placed in a uniform magnetic field, specifically finding the magnetic field outside the shell and the surface current density. It is established that the net magnetic field inside the shell is zero, and boundary conditions at the surface are derived. The magnetic dipole moment is calculated, leading to a relationship between the magnetic moment and the external magnetic field. However, confusion arises regarding the calculation of surface current density, with references made to textbook methods that involve tangential magnetic field continuity. The conversation emphasizes the need for clarity on how to relate the magnetic moment to the surface current's rotation.
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Homework Statement


A superconducting spherical shell of radius R is placed in a uniform magnetic field ##\vec{B_0}##
1)Find the magnetic field everywhere outside the shell
2)the sutface current density

Homework Equations


Inside the shell the net magnetic field is 0, and at the surface also.
The magnetic field of a magnetic diople of moment ##\vec{m}## is
$$\vec{B_m}=\frac{μ_0}{4\pi}[\frac{3(\vec{m}.\vec{r})\vec{r}}{r^5} - \frac{\vec{m}}{r^3}]$$

The Attempt at a Solution



The boundary condition at the surface which is at an angle ##\theta## with the vertical is
$$\vec{B_{0,\hat{n}}}+\vec{B_{m,\hat{n}}}=0$$
So,$$B_0\cos{\theta}+\frac{μ_0}{4\pi}(\frac{2m\cos{\theta}}{R^3} )=0$$
Therefore at $$\vec{m}=-(\frac{2\pi}{μ_0})R^3 \vec{B_0} $$,the boundary condition are satisfied on the surface of the shell.Hence,$$\vec{B}=\vec{B_0}-\frac{(3R^3)(\vec{B_0}.\vec{r})\vec{r}}{2r^5} + \vec{B_0}(\frac{R^3}{2r^3})$$
But i can't find the surface current density in this way. In my textbook,the author has written that we can find that using tangential B's continuity though i didn't get that.
 
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You calculated m as function of B and then plugged in m as function of B again (and I'm a bit surprised the terms don't cancel). You need m as function of the rotation of the surface current.
 
mfb said:
You calculated m as function of B and then plugged in m as function of B again (and I'm a bit surprised the terms don't cancel). You need m as function of the rotation of the surface current.
I know that way,but it is also a valid process i think.
You can see page 305 of "A Guide to Physics Problems" by Cahn and Nadgorny
 
Here it is
 

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