What is the thinnest film for strong reflection of visible light?

AI Thread Summary
The discussion focuses on determining the thinnest oil film that produces strong reflection for visible light at a wavelength of 700 nm. The initial calculation suggests a thickness of 140 nm, but this is identified as incorrect. The correct approach involves applying the Law of Refraction to find the wavelength in the oil film, which is calculated to be 560 nm. The user grapples with understanding the relationship between the wavelength in air and in the oil, emphasizing the need for clarity on the refraction principles. The conversation highlights the importance of accurately applying optical formulas to achieve the desired result.
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Homework Statement


A very thin oil film(n=1.25) floats on water(n=1.33). What is the thinnest film that produces a strong reflection for visible light with a wavelength of 700nm?


Homework Equations


\lambda=(2nd)/(m-0.5)
d=(m-0.5)*(\lambda/2n)
thinnest film has m=1

The Attempt at a Solution


d=(0.5*700)/(2*1.25)=140nm
This answer is incorrect. Is there a problem in my technique?
 
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It seems to me the film will just be a half wavelength thick so that light traveling through it to the water surface and back will be a full wavelength delayed and so will constructively interfere with waves reflected off the film surface.

Of course that will be in terms of the wavelength in the film, so you'll need a Law of Refraction formula that let's you computer the wavelength in the film.
 
I was not introduced to the law of refraction. I did look ahead in my physics book catch a glimpse of what it is about. This is my attempt at just hucking the formulas.
\vartheta=arcsin(n2/n1)=arcsin(1.25/1.33)=1.222
\vartheta*\lambda=1.222*700=855.5nm

Is this correct?
 
If I understand this correctly, it says the wavelength is 700 nm in AIR.
In the oil film the wavelength will be reduced by a factor of 1.25 to 560 nm.
The part of the law of refraction you need is that
\lambda1/ \lambda2 = n2/n1
Use n1 = 1 for air, n2 = 1.25 for the oil.
 
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