1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Superposition, Moving Around CKT Elements

  1. May 31, 2013 #1

    2. V=IR, Voltage division, KCL, KVL

    3. When I short out the dependent current source by replacing it with an open, can I switch the location of the independent source and the 20 ohm resistor so I can do a voltage division to find the voltage across the 20ohm resistor which is then equal to Vo because they are in parallel?
    Last edited by a moderator: May 31, 2013
  2. jcsd
  3. May 31, 2013 #2

    The Electrician

    User Avatar
    Gold Member

    The conventional wisdom is that you can't deactivate dependent sources when doing superposition. See this for more info:


    But, if you did short the dependent current source in your circuit, the 20 ohm resistor would also be shorted, wouldn't it? So your voltage divider wouldn't have any output since one leg of it would be zero ohms.
  4. May 31, 2013 #3


    User Avatar

    Staff: Mentor

    "short" ≠ "open"

    I'd retain the dependent current source where it is. Find the contribution of the voltage source to Vo. Then find the contribution of the current source to Vo.
  5. Jun 1, 2013 #4

    rude man

    User Avatar
    Homework Helper
    Gold Member

    Solve the equations twice, once with the 3A source removed and once again with the 15V source set to zero volts (a wire in other words).

    In each case the dependent current source 2Ix must remain in place.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted