Superposition of Electric Fields

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SUMMARY

The discussion focuses on calculating the electric field at point A due to two point charges, q1=2.00 μC and q2=3.00 μC for part (a), and q1=2.00 μC and q2=-3.00 μC for part (b). The correct approach involves using Coulomb's law to determine the electric field from each charge separately using the formula E = kQ/r², where k is Coulomb's constant. The superposition principle is applied to combine the electric fields from both charges to find the resultant field at point A. The expected result for part (a) is confirmed to be 1.26E5 N/C.

PREREQUISITES
  • Coulomb's Law for electric forces
  • Understanding of electric fields and their superposition
  • Knowledge of point charge calculations
  • Familiarity with the concept of electric field strength (E = kQ/r²)
NEXT STEPS
  • Study the principle of superposition in electric fields
  • Learn about the applications of Coulomb's Law in electrostatics
  • Explore the concept of electric field lines and their representation
  • Investigate the effects of multiple charges on electric fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone seeking to understand electric field calculations and the superposition principle in electrostatics.

Jimerd
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I know this problem is simple enough but I can't get the hang of it

Find the electric field at point A in the diagram if (a) q1=2.00 μC and q2=3.00 μC. (b) q1=2.00 μC and q2= -3.00 μC.


physics.png


Thank you.

P.S. If you can explain how you solved the problem that would be great. I'd really like to know what it is that I'm doing.

Homework Statement


Homework Equations


(9E9)(2E-6)(3E-6)/(0.5)^2=0.216 but the text tells me the answer is 1.26E5 for (a) so I'm not sure how to go about this.
 
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You're using Coulomb's law, that is only applicable to finding the force between two charges. You are looking for the field at A. To find the field from a point charge, you would use kQ/r^2, where k is Coulomb's constant, Q is the source charge, and r is the distance from the charge. Electric fields super impose, so you can find the field from each charge separately and then add them together.
 

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