Suppose B is moving with speed v away from A

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The discussion revolves around the application of K-calculus and Lorentz transformations to analyze the timing of an explosion event as perceived by observer B, who is moving away from A at speed v. Initially, there is confusion regarding the relationship between the K-calculus time factor k and the Lorentz factor γ, leading to the conclusion that k does not equal γ. The user resolves the issue by clarifying that the time light from the explosion reaches B is not the same as the time of the event, incorporating the light travel time into their calculations. They derive the relationship t' = kt/(1 + β) = γt, confirming the consistency of their findings. Additionally, the user inquires about the possibility of proving K-calculus using geometric methods.
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Homework Statement




Hi guys, i have a very simple question here about K-calculus.

Suppose B is moving with speed v away from A.

At time = t, an explosion (event) occurs in A, sending light in all directions.

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According to the K-Calculus,

The time the explosion occurred in B would be:

t' = kt


But, using lorentz transformations:

t' = γ(t - vx/c2)

Since x = 0,

t' = γt


But it is quite clear that k≠γ..



Nevermind, I have solved it:

Time light from event received by B ≠ Time of event

Bu rather, the observer takes into account and B compensates for the time needed for light from the event to travel to him:

t' = kt - (v/c)t'

t' = kt/(1 + β) = γt (Shown)
 
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Also on a side note, is it possible to prove the K-calculus using geometry? Which basically says that 'u' length along the ct axis would translate into 'k*u' length along the ct' axis..
 
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