Surface Integral Homework: Flux Through a Cylinder

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SUMMARY

The discussion focuses on calculating the flux through a cylinder of radius R and height h using the formula Flux = ∫∫FndS over S. The vector field F is defined as (ix + jy)*ln(x²+y²). The solution involves finding the unit normal vector to the cylinder's surface, leading to the integral ∫∫((x²+y²)/√(x²+y²))*ln(x²+y²)dS. The participant confirms that substituting x²+y² with R² is valid, resulting in the final answer of 4πhR²ln(R).

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Homework Statement



The problem asks to find the flux through a cylinder of radius R and height h.

Homework Equations



Flux = ∫∫FndS over S

F = (ix + jy)*ln(x2+y2)

The Attempt at a Solution



After finding the unit normal vector (n) to the curved surface of the cylinder, the integral simplified down to:

∫∫((x2+y2)/√(x2+y2))*ln(x2+y2)dS

I'm wondering if it is ok to replace x2+y2 with R2. Then the integral would be:

∫∫Rln(R2)dS

and since R is a constant

Rln(R2)∫∫dS

= 4*pi*hR2ln(R). which is the correct answer
 
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Yeah,that's OK because you're computing \vec{F}\cdot\hat{n} only on the surface of the cylinder!
 
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