# Surface integral in Spherical Polar

1. Mar 2, 2015

### samjohnny

1. The problem statement, all variables and given/known data
Attached.

2. Relevant equations

3. The attempt at a solution
Hi,

Ok, so for the first part of this question it asks to evaluate the integral of the dot product between A and dS. The magnitude of dS is as shown above, and it is in the radial direction in spherical polar coordinates. Here, A(r) is the unit vector of θ in spherical polar. And since we know that the polar direction θ and the radial direction are orthogonal to each, their dot product must = 0. Therefore, the integral of A.dS must be equal to zero. Is this line of thought correct?

Thanks.

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2. Mar 2, 2015

### HallsofIvy

Staff Emeritus
No, the direction of $d\underline{S}$ is not "in the radial direction". The "vector differential of area" is $(a^2cos(\theta)sin^2(\phi)\vec{i}+ a^2sin(\theta)sin^2(\phi)\vec{j}+ a^2 sin(\phi)cos(\phi)\vec{k})d\theta d\phi$. That is not a multiple of a radial vector which would be of the form $r cos(\theta)sin(\phi)\vec{i}+ r sin(\theta)sin(\phi)\vec{j}+ r cos(\phi)\vec{k}$.

3. Mar 3, 2015

### samjohnny

Thanks for the reply. But if I'm thinking about this right, couldn't you factor out of that vector the scalar a^2*sin(α) which would leave the unit vector in the radial direction? Please see the attached.

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