1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Surface integral or Divergence Theorem confused?

  1. Feb 26, 2012 #1
    1. The problem statement, all variables and given/known data

    Find the Volume
    ∫∫ xy DA
    where R is the region bounded by by the line y=x-1 and the parabola y^2=2x+6.

    2. Relevant equations

    ∫∫ xy dx dy

    3. The attempt at a solution

    first i found the intersection of the above equations . which is (5,4) to (-1,-2) . then i simple put the values in the limits of the integral
    i-e

    ∫(from y= -2 to y=4) ∫(from x= y+1 to x= (y^2-6)/2 ) xy dx dy

    and solve it and finaly got 52/3.

    is this the right method and limits are correct or not ?
    or i have to use here divergence theorem

    can somebody explain the word VOLUME in the question ?
     
  2. jcsd
  3. Feb 26, 2012 #2

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    The word "volume" is an error. Clearly that is a two dimensional figure so it has area not volume.
     
  4. Feb 26, 2012 #3
    so that means my method is correct?

    but someone says

    If the problem really is to find a "volume", it should read ∫ ∫ |xy| dA because the integrand is not positive everywhere on the region given.

    Can't be sure, but that's probably not what the author intended. He just wants you to integrate xy over the region. It has the form ∫ ∫ z(x, y) dA which is a volume integral if z(x, y) is non-negative over the region.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Surface integral or Divergence Theorem confused?
Loading...