Suspending a Charged Droplet: Electric Field E Found by Millikan

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To suspend a charged droplet in a gravitational field, the electric field E must balance the gravitational force acting on the droplet. The relationship is given by the equation E = ((ρ g)/q) (4/3) ∏ R³, where ρ is the density, g is the gravitational acceleration, and q is the charge. The method used involves equating the electric force to the gravitational force, confirming the approach is valid. Millikan's experiments established that droplets carried integer multiples of the elementary charge e. The calculations presented align with the principles of force equilibrium in this context.
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Homework Statement



A spherical droplet of radius R and effective mass density ρ. carries a total charge q in a gravity field g. What electric field E iz, will suspend the charged droplet? Millikan found by this method that all droplets carried integer multiples ofnegative charge e= -1.6 x 10-coul.

Homework Equations



F=ma

The Attempt at a Solution



I would like to confirm if my attempt is okay or not. Please can you give explanation based on whatever method it is required to be solved in.

q E = ρ g (4/3) ∏ R3

E = ((ρ g)/q) (4/3) ∏ R3
 
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4real4sure said:

Homework Statement



A spherical droplet of radius R and effective mass density ρ. carries a total charge q in a gravity field g. What electric field E iz, will suspend the charged droplet? Millikan found by this method that all droplets carried integer multiples ofnegative charge e= -1.6 x 10-coul.

Homework Equations



F=ma

The Attempt at a Solution



I would like to confirm if my attempt is okay or not. Please can you give explanation based on whatever method it is required to be solved in.

q E = ρ g (4/3) ∏ R3

E = ((ρ g)/q) (4/3) ∏ R3

It makes sense to me. You equated the gravitational force to the electric force (in magnitude). You computed the mass by multiplying the density by the volume. I don't see any problems.
 
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