- #1
saminny
- 9
- 0
Hi,
As per Clariut's theorem, if the derivatives of a function up to the high order are continuous at (a,b), then we can apply mixed derivatives. I am looking at
http://en.wikipedia.org/wiki/Symmetry_of_second_derivatives
and I cannot understand in the example for non-symmetry, why the derivatives are not continuous and not equal. Can someone please explain that example?
thanks,
Sam
As per Clariut's theorem, if the derivatives of a function up to the high order are continuous at (a,b), then we can apply mixed derivatives. I am looking at
http://en.wikipedia.org/wiki/Symmetry_of_second_derivatives
and I cannot understand in the example for non-symmetry, why the derivatives are not continuous and not equal. Can someone please explain that example?
thanks,
Sam