# Homework Help: Systems of equation

1. Oct 9, 2008

### enibaraliu

1st: 32x-2y+2*3x-y-3=0
3x+31-y=4

2nd: 3y*$$\sqrt[x]{64}$$=36
5y*$$\sqrt[x]{512}$$=200

3rd: 9*5x+7*2x+y=457
6*5x-14*2x+2=-890

At first i treid to replace 3x with u , 3x=u and 3y=v but I don't know what to do then.

At 2nd, $$\sqrt[x]{64}$$ I replace with 26/x but then this be more complicate,and I don't know another way,please help me!!

2. Oct 9, 2008

### happyg1

For 1,
Cant you solve the second equation for $$3^x$$ and then plug it back in to the first one after you break it down using your exponent properties?

that's just suggestion at first glance.
CC