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Homework Help: Systems of equation

  1. Oct 9, 2008 #1
    1st: 32x-2y+2*3x-y-3=0

    2nd: 3y*[tex]\sqrt[x]{64}[/tex]=36

    3rd: 9*5x+7*2x+y=457

    At first i treid to replace 3x with u , 3x=u and 3y=v but I don't know what to do then.

    At 2nd, [tex]\sqrt[x]{64}[/tex] I replace with 26/x but then this be more complicate,and I don't know another way,please help me!!
  2. jcsd
  3. Oct 9, 2008 #2
    For 1,
    Cant you solve the second equation for [tex]3^x[/tex] and then plug it back in to the first one after you break it down using your exponent properties?

    that's just suggestion at first glance.
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