Thanks!Creating Detailed Math Questions with Cramster: A Scientist's Guide

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Cramster is highlighted as a useful tool for creating detailed math questions due to its inclusion of necessary mathematical symbols. The discussion centers around the existence of negatives axiom, confirming that for any real number 'a', there exists a real number 'b' such that a + b = 0. Participants express agreement on the validity of this axiom and appreciate the insights shared. The original poster seeks guidance on marking the forum thread as 'closed' or 'solved' now that their question has been answered. Overall, the conversation emphasizes the utility of Cramster and the collaborative nature of the forum in resolving mathematical queries.
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I've used Cramster to create my question in detail since it has the mathematical symbols I needed.

http://answerboard.cramster.com/advanced-math-topic-5-301680-0.aspx" .

Any advice, suggestions, ideas, and help is greatly appreciated.
Thank you very much!:smile:
 
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Number 4 reads:
"for any(or all) real number(s) 'a', there exists a real number (not a single one) 'b' such that a+b=0."
Whatever 'a' is, you can pick out the 'b'
This is true.

I agree with the first three.
CC
 
Statement 4 is the existence of negatives axiom I've always been taught:

"For every real number x there is a real number y such that x + y = 0."
 
Thanks to everyone who replied! It helped a lot!

I'm very new to this forum (just joined yesterday). Now how do I mark this forum as 'closed' or 'solved' so that people don't have to view it anymore since my question's been answered?
 
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Thread 'Finding the number of ways to arrange identical balls in a circle (3 different colors)'

I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
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Thread 'Greatest possible value of a constant in polynomial'

Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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