Tangent Line on a Parametric Curve

suchgreatheig
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Homework Statement


A curve is defined parametrically by x=sin3t, y=cos3t, 0≤ t ≤ 2pi. Find the equation of the line tangent to the curve at the point defined by t=2pi/9.


Homework Equations





The Attempt at a Solution


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suchgreatheig said:

The Attempt at a Solution


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Since you need to find the equation of a tangent, what do you need to find this equation?
 
I know that I need a derivative which I got as -3sinst/3cos3t, but I'm stuck from there.
 
suchgreatheig said:
I know that I need a derivative which I got as -3sinst/3cos3t, but I'm stuck from there.

so if dy/dx=-sin(3t)/cos(3t), what is the gradient when t=2π/9 ?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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