Tangent Line to Curve of Intersection: Calculating the Normal and Cross Product

Yitin
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Homework Statement



Find parametric equations for the tangent line to the curve of intersection of the cone z=√(x2 + 4y2) and the plane 3z = x + 2y + 8 at the point (3,2,5)

2. The attempt at a solution

I was trying to make the two Zs equal to each other, and solve for x or y, but I couldn't get any of them separate. I tried squaring both of them so they would both have things like X2. It didn't work out.
 
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Yitin said:

Homework Statement



Find parametric equations for the tangent line to the curve of intersection of the cone z=√(x2 + 4y2) and the plane 3z = x + 2y + 8 at the point (3,2,5)

2. The attempt at a solution

I was trying to make the two Zs equal to each other, and solve for x or y, but I couldn't get any of them separate. I tried squaring both of them so they would both have things like X2. It didn't work out.

That's enough reason to try a different approach. Remember that the curve of intersection of two surfaces lies in both surfaces. So if you calculate the normal to each surface at a point on the surface, each normal will be perpendicular to the curve at that point. So the cross product of the normals will be tangent to the curve. And gradients are perpendicular to surfaces...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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