Taylor Approximation: Show ∫f'(x)dx/f(x)=ln|f(x)|+C

Nugso
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Homework Statement



Show that ∫f'(x)dx/f(x) = ln|(f(x)|+C where f(x) is a differential function.


Homework Equations



First order Taylor approximation? f(x)=f(a)+f'(a)(x-a)


The Attempt at a Solution



Well, I'm not really sure how to approach the question. It's my Numerical Methods homework, so I think I have to do it by using Taylor approximation. By applying the first order Taylor approximation I get:

ln|f(x)|=y, ln|f(a)| - ln|(f(x)| = (a-x)f'(x)/f(x)

ln|(f(a)/f(x)| = (a-x)f'(x)/f(x)

I'm kind of stuck here. Am I right in thinking that Taylor approximation is an appropriate way to approach the question?
 
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Nugso said:

Homework Statement



Show that ∫f'(x)dx/f(x) = ln|(f(x)|+C where f(x) is a differential function.


Homework Equations



First order Taylor approximation? f(x)=f(a)+f'(a)(x-a)


The Attempt at a Solution



Well, I'm not really sure how to approach the question. It's my Numerical Methods homework, so I think I have to do it by using Taylor approximation. By applying the first order Taylor approximation I get:

ln|f(x)|=y, ln|f(a)| - ln|(f(x)| = (a-x)f'(x)/f(x)

ln|(f(a)/f(x)| = (a-x)f'(x)/f(x)

I'm kind of stuck here. Am I right in thinking that Taylor approximation is an appropriate way to approach the question?

Start again: you are on the wrong track.
 
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Hi Ray, thanks for the reply. Would you mind giving me a hint? I really haven't a clue about the right track.
 
Why not take the derivative of the right-hand side?
 
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micromass said:
Why not take the derivative of the right-hand side?

I guess my teacher wants us to solve it by the difficult way, i.e using appropriate ways.
 
Nugso said:
I guess my teacher wants us to solve it by the difficult way, i.e using appropriate ways.

There is nothing wrong with using the Fundamental Theorem of Calculus to solve the problem. To verify that ##\int f(x) \, dx = F(x) + C##, just check that ##F'(x) = f(x)##.

That is an absolutely 100% correct way to do the question. In fact, such checking should always be done out of habit, whenever you are faced with a possible formula for the indefinite integral F(x) of an integrand f(x). That is a good way to catch errors.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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