I Teacher needs maths assistance please

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A university English teacher in China seeks assistance in adjusting exam marks from a range of 20 to 100 to a new range of 60 to 100 while maintaining proportional relationships. The proposed mathematical solution involves using the formula new = 0.5 * old + 50. This adjustment ensures that lower scores are elevated appropriately without distorting the relative performance of students. The discussion acknowledges the simplicity of the solution and the importance of verifying the problem's context. The teacher expresses gratitude for the guidance received.
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I teach English at a university in China. I don't want any of my students to fail so I need to adjust exam marks. The exam marks range from 20 to 100. I want to adjust them so that the marks will range from 60 to 100, but I want to retain the proportional relationship between the marks. So for example 20 out of 100 will become 60 and 60 out of 100 will become 80. I haven't had to do any maths for many years so can someone please let me know how to do this.
 
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Usually we require some effort and an attempt to solve the problem, because we cannot know whether your story is correct or only a nice trick to get homework solved. So my answer now isn't really allowed. However, I think I can make an exception, as the solution isn't really very complicated. You can use ##new = \dfrac{1}{2}\cdot \, old +50##
You can also find this solution graphically.
 
Thank you. I knew the answer was fairly simple and I could have proven what I said if necessary.
 
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