Telescope focal length homework

AI Thread Summary
The discussion revolves around solving two telescope-related homework problems. The first question involves calculating the size of the sun's image produced by a telescope with an 18m focal length, using the formula for image distance and magnification, resulting in an image size of 17cm. The second question asks for the object distance of a converging mirror with a 20cm focal length that produces an image twice the size of the object, prompting a request for alternative methods to derive the solution. Participants emphasize the use of geometry and similar triangles to approach the problems. The conversation highlights the importance of understanding the underlying principles of optics in solving these types of questions.
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Hey guys, I am really stuck on my homework review and really require help! Someone please help ! :(

Homework Statement


Question 1: A telescope has a focal length of 18m. If the suns diameter is about 1.39 x 10^9m and its distance from Earth is 1.49 x 10^11, how large is the telescopes image of the sun.
2. A converging mirror produces an image twice the size of the obbect. If the focal length is 20cm, find the object distance.

Homework Equations


1/f = 1/do + 1/di
m = -di/10 = hi/10
- FOR BOTH


The Attempt at a Solution


f = 18m
do = 1.49 x 10^11
ho = 1.39 x 10^9

1/f = 1/do + 1/d1
1/f - 1/do = 1/di
-0.56 = di
m = - (di)/do
= - (-0.56m / 1.49 x 10^11)
3.76 x 10 = m
m = hi / ho
3.76 x 10 ^10 = hi / 1.39x 10 ^...

THE FINAL ANSWER FOR THE QUESTION IS 17CM
 
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Q. 1
Image of the sun is framed at the focus of the objective. If you take two diametrically opposite rays from the sun to from the image at the focus, the optical center of the objective, ho and hi form two similar triangles. So
do/ho = di/hi. di is the focal length of the objective. Find hi.
Q.2 Show your attempt.
 
Hey there.. we haven't quite learned anything about the formula you told me about where di = f. the hi/di. Isn't there any other way i can possibly do it?
 
rl.bhat just used simple geometry to derive that equation, so I'm fairly certain that it's probably the solution your professor/teacher is looking for.
 
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