1/(16n^2-8n-3)(adsbygoogle = window.adsbygoogle || []).push({});

I want to find the sum of this series from n=1 to infinity

By partial fraction I find

1/(16n^2-8n-3)=1/((4n+3)(4n-1))

which can be written

(1/4)(1/(4n-1)-1/(4n+3))

The sum of this is 1/12, but the right answer is 1/4. What is wrong?

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# Homework Help: Telescoping sum

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