Temperature change in an isentropic flow of an ideal gas

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SUMMARY

The discussion centers on the confusion surrounding the definition of an isentropic process in the flow of an ideal gas, specifically regarding its reversible and adiabatic nature. Participants clarify that while isentropic processes imply no heat transfer with surroundings and no friction losses, temperature gradients within the gas can lead to internal heat transfer, which is inherently irreversible. The example of gas-filled balloons illustrates that rapid expansion can be adiabatic, yet the presence of temperature gradients raises questions about the reversibility of such processes.

PREREQUISITES
  • Understanding of isentropic processes in thermodynamics
  • Familiarity with the principles of adiabatic and reversible processes
  • Knowledge of the second law of thermodynamics
  • Basic concepts of compressible fluid dynamics
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  • Study the implications of the second law of thermodynamics on heat transfer
  • Explore the concept of temperature gradients in compressible flows
  • Learn about the characteristics of adiabatic processes in ideal gases
  • Investigate the relationship between viscosity and irreversibility in fluid dynamics
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Students and professionals in thermodynamics, mechanical engineers, and anyone interested in the behavior of ideal gases during isentropic processes.

citrouille
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I am a bit confused by the definition of an isentropic process in the flow of an ideal gas.

isentropic implies reversible & adiabatic.

for a process to be reversible, there are no losses to friction (viscosity in this case),
for a process to be adiabatic, there is no heat transfer with the surroundings.

That being said, when a compressible gas flows through a nozzle, there is a temperature change. When this happens, a temperature gradient occurs. Where there is a temperature gradient, heat transfer occurs within the gas. I was always taught that, according to the 2nd principle of thermodynamics, a heat transfer due to a temperature gradient (from hot -> cold areas) is irreversible...which is directly contradicting the definition of a reversible & adiabatic flow...

Hope this is a pertinent question...

Thanks a lot for any help.
 
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citrouille said:
I am a bit confused by the definition of an isentropic process in the flow of an ideal gas.

isentropic implies reversible & adiabatic.

for a process to be reversible, there are no losses to friction (viscosity in this case),
for a process to be adiabatic, there is no heat transfer with the surroundings.

That being said, when a compressible gas flows through a nozzle, there is a temperature change. When this happens, a temperature gradient occurs. Where there is a temperature gradient, heat transfer occurs within the gas. I was always taught that, according to the 2nd principle of thermodynamics, a heat transfer due to a temperature gradient (from hot -> cold areas) is irreversible...which is directly contradicting the definition of a reversible & adiabatic flow...

Hope this is a pertinent question...

Thanks a lot for any help.

Imagine a bunch of balloons containing gas. Imagine that they expand when they fly out of a window. The expansion of the gas cools the gas in the balloons. Yet, there is not any significant heat exchange between the balloons. That's because there's not enough time permitted for that exchange of heat to be significant. Thus, it is adiabatic.
 
kmarinas86 said:
Imagine a bunch of balloons containing gas. Imagine that they expand when they fly out of a window. The expansion of the gas cools the gas in the balloons. Yet, there is not any significant heat exchange between the balloons. That's because there's not enough time permitted for that exchange of heat to be significant. Thus, it is adiabatic.

I do not have a problem with the fact that the process is adiabatic (no heat transfer with the surroundings). My problem is with the fact that the transformation is reversible, and yet there is a spatial temperature gradient which would cause heat transfer within the gas (not with the surroundings). Heat transfer due to a temperature gradient within the gas is irreversible...maybe I'm thinking too much...sorry
 
citrouille said:
kmarinas86 said:
Imagine a bunch of balloons containing gas. Imagine that they expand when they fly out of a window. The expansion of the gas cools the gas in the balloons. Yet, there is not any significant heat exchange between the balloons. That's because there's not enough time permitted for that exchange of heat to be significant. Thus, it is adiabatic.

I do not have a problem with the fact that the process is adiabatic (no heat transfer with the surroundings). My problem is with the fact that the transformation is reversible, and yet there is a spatial temperature gradient which would cause heat transfer within the gas (not with the surroundings). Heat transfer due to a temperature gradient within the gas is irreversible...maybe I'm thinking too much...sorry

If you count the separate balloons as members of the same "gas", you can easily see how there is not significant transfer of heat, not even between parts of the gas.
 
kmarinas86 said:
If you count the separate balloons as members of the same "gas", you can easily see how there is not significant transfer of heat, not even between parts of the gas.

That makes more sense ! Thanks a lot for clearing that up.
 

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