Homework Help: Tension angle

1. Apr 22, 2012

fisselt

1. The problem statement, all variables and given/known data
Weight suspended by 3 cords. 1 from the weight goes up vertically to the knot. The next goes left 30° below horizontal and the last goes to the right 45° above horizontal.

2. Relevant equations
f=ma

3. The attempt at a solution
I dont think I've ever worked a problem with a cord below horizontal. So I'm stumbling a bit.

Since there's only 1 cord above horizontal (T1) it should carry the whole y force. So, in y T1=T2+T3
And, in x the left and right cords must be equal T1=T2

T1sin(45)=T2sin(30)+mg

Not sure about the rest. Any help?

2. Apr 22, 2012

OldEngr63

The problem statement is somewhat confusing. A figure would really help.

3. Apr 22, 2012

fisselt

Attached Files:

• Tension.jpg
File size:
10.8 KB
Views:
113
4. Apr 22, 2012

azizlwl

As the object not going up or down
it's too not going left or right, equal forces must be there to make it in equilibrium.

5. Apr 23, 2012

OldEngr63

You simply need to sum forces, both horizontal and vertical, at the junction point, and require that both sum to zero. That will give you everything you need.