1. The problem statement, all variables and given/known data Weight suspended by 3 cords. 1 from the weight goes up vertically to the knot. The next goes left 30° below horizontal and the last goes to the right 45° above horizontal. 2. Relevant equations f=ma 3. The attempt at a solution I dont think I've ever worked a problem with a cord below horizontal. So I'm stumbling a bit. Since there's only 1 cord above horizontal (T1) it should carry the whole y force. So, in y T1=T2+T3 And, in x the left and right cords must be equal T1=T2 T1sin(45)=T2sin(30)+mg Not sure about the rest. Any help?