Tension in a rope connecting charged spheres.

AI Thread Summary
The discussion revolves around a problem involving two positively charged spheres connected by a rope, where both are in static equilibrium. The initial analysis incorrectly concludes that the tension in the rope is zero due to equal and opposite forces between the spheres. However, the correct approach involves recognizing that tension acts on both spheres in opposite directions, and the net force must sum to zero for static equilibrium. To find the tension, one should isolate a sphere and analyze the forces acting on it using a Free Body Diagram. The key takeaway is that the tension is not zero and must be calculated by considering the forces acting on one sphere.
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Homework Statement


Two positive charged spheres, with masses m = 2.0 g and with the same charge 2 µC are connected by a rope that is a distance of 5 cm. The charged spheres are at rest and the system is in static equilibrium.

Homework Equations



N/A.

The Attempt at a Solution


The system is in static equilibrium, which implies the net force is 0:
\displaystyle\sum_i (f_x)_i = F_1on2 - F_2on1 + T = 0 => T = F_2on1 - F_1on2 = \frac{kq^2}{r^2} - \frac{kq^2}{r^2} = 0.

Thus, I end up with tension being equal to zero since the force the charged sphere on the left exerts on the charged sphere on the right is equal and opposite to the forced the charged sphere on the right exerts on the left.

But, I have the wrong answer. Where did I go wrong?
 
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Tension acts on both spheres, and in opposite directions. If you sum all the forces you'll end up with the unsurprising result that |F2on1| = |F1on2|, that is, they are both pushing each other with the same magnitude of force.

To find the tension, isolate one of the spheres and draw the Free Body Diagram. Sum the forces there. What should they sum to for static equilibrium?
 
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