Tension problem calculate theta

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    Tension Theta
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To determine the tension in the horizontal rope DE, the angle θ must first be calculated, which is suggested to be twice the inverse tangent of 1/3. The weight of the mass m creates a reaction force that is evenly distributed at the points of contact with the ground. The discussion emphasizes the importance of applying equilibrium principles by summing forces and torques to ensure they equal zero. There is uncertainty regarding the calculation of θ, as it appears that the necessary information may not be fully provided. A visual representation of the problem is requested to aid in understanding the setup and calculations.
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Homework Statement



A cylinder of radius R and mass m is lodged between cross pieces that make an angle θ with each other. The cross pieces of negligible mass are connected in point C, with lengths AC = BC = 2R and CD = CE = 3R. Determine the tension in the horizontal rope DE. You may assume smooth floor.

Homework Equations

The Attempt at a Solution


My starting point was to calculate theta, which would be twice the inverse tangent of 1/3. I also know that the weight of the mass m will partner a reaction force that is spread evenly between the two points of contact with the ground. However I'm not too sure where to go from here and any help would be much appreciated!
 
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A picture would be really helpful.
 
[PLAIN]http://Screen [/PLAIN] shot [/PLAIN] [PLAIN]http://Screen [/PLAIN] Shot 2015-03-08 at 19.06.54[/PLAIN]
Here it is- I thought I'd attached it, sorry!
 
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Screen Shot 2015-03-08 at 19.06.54.png
 
Equilibrium problems always come down to summing forces and torques and setting the sums equal to zero. Consider the equilibrium of the cylinder and of one of the cross pieces.

How did you calculate ##\theta##? I don't think it can be determined from the information given, and the tension you find will be a function of ##\theta##.
 

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