Tension Problem: Lifting Yourself

  • Thread starter Thread starter joshk_bra
  • Start date Start date
  • Tags Tags
    Lifting Tension
AI Thread Summary
The discussion revolves around the physics problem of whether a man can lift a platform by pulling on a rope through a frictionless pulley. The key forces at play include the weight of the man and the platform, tension in the rope, and gravitational force. A participant expresses uncertainty about the correct equations to use, initially suggesting T - Ft = ma but later clarifying their understanding of the forces involved. They conclude that the total force exerted must equal the combined weight of the man and the platform for upward acceleration to occur. The conversation highlights the application of Newton's laws in analyzing the tension required to lift the platform.
joshk_bra
Messages
2
Reaction score
0

Homework Statement



Lifting yourself. A man stands on a platform as shown in the figure below, and pulls up
on a rope that winds through a frictionless pulley attached to the platform. The other end
of the rope is attached to the ceiling. The mass of the man is m, and the combined mass of
the platform and pulley is M. Can the man lift the platform off the ground if he pulls hard
enough? If so, find the minimum tension required to give the platform a positive (upward)
acceleration, thus lifting it off the floor.



http://i86.photobucket.com/albums/k...yHomework003pdf-AdobeReader.jpg?t=1284942733"

Homework Equations



M = Pulley and Platform total mass

m = Mass of the man

The Attempt at a Solution



Well in class i didn't learn that about tension on a pulley system. But I believe the only forces acting on this is the total weight(m + M), Tension, and Gravity

so i was thinking the equation would loo something like T - Ft = ma?

Im not to sure about my equation, but i was wondering if someone would help me out with this problem

Thanks!
 
Last edited by a moderator:
Physics news on Phys.org
I do not think so. If he was to pull on the rope, the force that he puts on the rope would be transferred downwards on the platform he is trying to pull up.

So if he exerts 500 N of force pulling the rope up, it doesn't matter. It's equalled out by force pushing the platform down exerted by the man.

Newton's 3rd law.
 
Well i did more research and from it, i got that the 2 ropes are pulling up on the block and that they are equal( F and T).

so F + T = 2F = mg + Mg or F = (mg + Mg)/2.

Mg + mg is the total weight
Is this correct?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top