Tension Strongman problem from Physics

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When the strongman suspends a 10-pound telephone book with two vertical strands, the tension in each strand is 5 pounds. If the strands are pulled horizontally, the tension in each strand cannot be determined as it would require a vertical force component, which is impossible with horizontal strands. The discussion highlights that the vertical force from the strands must equal the weight of the book, leading to the equation 2T sin(θ) = 10 pounds. As θ approaches 0, the tension T becomes uncalculable, indicating that maintaining horizontal strands to support the weight is not feasible. The conversation concludes that perfect horizontal support is impractical, similar to how power lines sag under weight.
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Tension "Strongman" problem from Physics!

This is the question:
When the strongman suspends the 10 lbs telephone book with the rope held vertically, the tension in each strand of the rope is 5 lbs. If the strongman could suspend the book from the strands pulled horizontally, the tension in each strand would be how much?

A picture of it is at this website: http://www.physics.uwo.ca/ugrad/p02.../p021_lec12.pdf with a picture of a guy holding a textbook.

Any answers? And reasons for the answers?

Thanks!
 
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I wasn't able access the website given. Since the telephone book weighs 10 pounds and we are told that the "tension in each strand" is 5 pounds, are we to assume there are 2 strands?

It isn't possible to support the book with strands that are literally horizontal- there would be no vertical component of force.

Assuming that the two ropes make angle θ with the horizontal and have tension T, then the vertical component of force for each strand is T sin(θ)- the two together 2 T sin(θ) and that must be 10 pounds: 2 T sin(θ)= 10 so T= 5/sin(&theta).
 
Thanks!

I hope you didn't spend too much time doing that! The answer did turn out to be an uncalculatable amount- it is impossible to make it perfectly straight. My teacher mentioned how power lines are bent down too...
 
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