OmCheeto said:
...
Outside temperature is 43°F ( 6.11 °C )
Specific heat capacity of my house is 5000 Btu/°F ( 2.6 kwh / °C )
R-value is 13 ( (2.3 m2 °C) / watt )
Conductive surface area is 1900 ft2 ( 176 m2 )
If the house is heated to 75°F ( 23.9°C ) at 6 am, what will be the temperature in the house, 16 hours later?
And the answer is: 62.8 °F ( 17.1°C )
So one Powerwall unit will work for me.
Though, I'm retired, and don't get out much in the winter.
2 years ago, I would have laughed at heating my house to such a ridiculous temperature while I was at work all day.
I think I'll work on the heat capacity of an auxiliary water heater next.
I found one for $1,107.59 with a 105 gallon capacity. It has a 150°F maximum temperature.
Since it won't be hooked to the water mains, the associated plumbing shouldn't be too complicated, nor spendy.
I generally keep my house around 65°F in the winter.
And if it's less than 60°F ( 15.6 °C ) after 16 hours, how much water, heated to 150°F ( 65.6°C )would be required to maintain the minimum temperature at 60*F?
This shouldn't take too long to figure out.
105 gal * 8.34 lb / gal = 876 lb
1 btu = 1°F lb
ΔT water tank = 150°F - 65°F = 85°F
x btu = 876 lb * 85°F = 74,400 btu / 3400 btu/kwh = 21.8 kwh
ΔT interior exterior = 65°F - 43°F = 22°F
power loss at 22°F = 940 watts
21.8 kwh / .94 kw = 23.2 hours
required hours (off-peak): 16
7.8 hour surplus
hmmm...
That sounds ridiculously wrong.
Though, a 22°F ΔT isn't that much.
Reality check:
Ave temp for Dec 2014: 43°F
days measured: 34
actual kwh heating used: 1170 kwh
theoretical calculated: 770 kwh ( 0.94 kw * 24 hr/day * 34 days )
Not quite off by a factor of two. I'm guessing my R-value must be too high.
Anyways, this Powerwall thing should work for me.
Perhaps tomorrow I'll figure out the ROI on this new system.